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P19 · Spreading points in an L
· Discussion
关于此题n=4已达最优的证明
HwaterB
#40
19d ago
分成三个小正方形,若最小距离大于sqrt2,则每个小正方形各自最多放一个,抽屉原理易证放不了四个,故sqrt2就是最优
HwaterB
#40
19d ago
同理直角三角形那题的n=4也可证
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关于此题n=4已达最优的证明 — MinMax Arena