P24 · Extremal configurations · Formed here · Medium

The smallest triangle in an L · n = 6

Place n points inside an L-shape (a 2 × 2 square missing its top-right 1 × 1 corner) so that the smallest triangle formed by any three points has the largest possible area.

Instancen = 6
ObjectiveMaximize the smallest triangle's area

Record comparison

the smallest triangle's area · Higher is better
RecordValue / intervalAuthor / holderSource
External best known——No reference listed
Site record0.5邱仲普Record details ↓

Formal definition

  • ContainerAn L-shaped region formed by removing the top-right 1 × 1 square from a 2 × 2 square: the lower-left corner is at (0, 0), and the removed region is where x > 1 and y > 1
  • SubmissionExactly n points, with no three collinear
  • ConstraintsEvery point must lie inside the container or on its boundary
  • ScoreA(P) is the minimum triangle area over all triples of points; internally, the verifier compares 2A(P) using exact arithmeticA(P)=12min1≤i<j<k≤n|det(pj−pi,pk−pi)|
  • ObjectiveMaximize A(P)
Open full editor ↗

Layout shown: site record

2y0
0x2
VERIFIED CONSTRUCTIONthe smallest triangle

Getting a feel for it

How to push the minimum area up

Simply spreading the points out evenly is not enough: whenever three points are nearly collinear, the triangle they form collapses into a thin sliver. In an L-shaped region where two corridors meet at a corner, lining points up neatly along the straight edges or diagonals almost inevitably creates near-collinear triples, so high-scoring configurations are typically completely asymmetric.

Current status

Heilbronn's triangle problem inside an L-shape (a 2 × 2 square missing its top-right 1 × 1 corner) is an original variant introduced on this site, with no prior published literature. Every n is unexplored territory, and the current leaderboard records are the best results known.

The record-holding arrangement for The smallest triangle in an L n = 6, 0.5
LAYOUT & HISTORY

Record details

Inspect the layout, solver notes and record history.

Record holder邱仲普
Solution methodAI · DeepSeek: DeepSeek V3
Challenge this record ↗Submit a proof / idea ↓Share a proof or bound argument in the discussion board. Accepted contributions earn proof points.
Record holder's solver noteNo solver note yet (expand)+

The record holder has not shared a solver note yet.

Record history (1 changes)
  1. 邱仲普AI · DeepSeek: DeepSeek V3
    0.0692820324→0.5
ANSWER FORMAT

How to write your answer

The container is a square of side 2 with its top-right 1 × 1 quarter removed: the origin (0, 0) is its lower-left corner and the missing piece is where x and y are both greater than 1. Coordinates are written as plain decimals such as "0.5", to at most nine decimal places.

Submit a points array with each coordinate written as a decimal string (e.g. "0.5").

The current leader's answer

{
  "points": [
    [
      "2",
      "1"
    ],
    [
      "1",
      "2"
    ],
    [
      "0",
      "2"
    ],
    [
      "0",
      "1"
    ],
    [
      "1",
      "0"
    ],
    [
      "2",
      "0"
    ]
  ]
}
Submission format and technical detailsOpen this when you are ready to prepare a JSON answer+

Instance parameters

{
  "n": 6
}

The current leader's answer

{
  "points": [
    [
      "2",
      "1"
    ],
    [
      "1",
      "2"
    ],
    [
      "0",
      "2"
    ],
    [
      "0",
      "1"
    ],
    [
      "1",
      "0"
    ],
    [
      "2",
      "0"
    ]
  ]
}

Submit a points array with each coordinate written as a decimal string (e.g. "0.5"). · Verifier v1.0.0

DISCUSSION

Discussion

Discuss strategies, share construction methods, or ask questions. Any signed-in user can post under their public byline and unique #UID. New posts appear after moderation.

No threads yet. Start the first discussion.