The smallest triangle in an L · n = 9
Place n points inside an L-shape (a 2 × 2 square missing its top-right 1 × 1 corner) so that the smallest triangle formed by any three points has the largest possible area.
Record comparison
the smallest triangle's area · Higher is better| Record | Value / interval | Author / holder | Source |
|---|---|---|---|
| External best known | — | — | No reference listed |
| Site record | 0.1839882678214425815 | 邱仲普 | Record details ↓ |
Formal definition
- ContainerAn L-shaped region formed by removing the top-right 1 × 1 square from a 2 × 2 square: the lower-left corner is at (0, 0), and the removed region is where x > 1 and y > 1
- SubmissionExactly n points, with no three collinear
- ConstraintsEvery point must lie inside the container or on its boundary
- ScoreA(P) is the minimum triangle area over all triples of points; internally, the verifier compares 2A(P) using exact arithmetic
- ObjectiveMaximize A(P)