Heilbronn minimum tetrahedron volume · n = 5
Place n points in the unit cube so that the smallest tetrahedron formed by any four of them is as large as possible.
Record comparison
minimum tetrahedron volume · Higher is better| Record | Value / interval | Author / holder | Source |
|---|---|---|---|
| Proven optimum | 1/6 | NUE_13 #31 | MinMax Arena ↗ |
| Site record | 1000000000000000000000000000 / (6·10²⁷) | 邱仲普 | Record details ↓ |
The continuous optimum is proved, so competition submissions are closed. Historical records and contribution points are retained. Because finite-decimal coordinates cannot attain this value exactly, the current certificate is not claimed optimal on the nine-decimal grid.
Formal definition
- ContainerThe unit cube [0, 1]³ with opposite corners at (0, 0, 0) and (1, 1, 1)
- SubmissionExactly n points, no four of them coplanar
- ConstraintsEvery point lies inside the cube or on its boundary
- ObjectiveMaximize the minimum tetrahedron volume over all quadruples, compared exactly via the 3×3 determinant of three edge vectors