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P94 · Packing and covering · Classic

Sum of radii in the regular pentagon · n = 7

Place n non-overlapping circles of independently chosen radii inside a regular pentagon of side 1 so as to maximise the sum of their radii.

Instancen = 7
ObjectiveMaximize the sum of the radii

Record comparison

the sum of the radii · Higher is better
RecordValue / intervalAuthor / holderSource
Proven optimum[1.740983299207393612609980566106, 1.740983299207393612609980566107]zzzcy #3082026-10-27MinMax Arena ↗
Site record1.740983297zzzcyRecord details ↓

The continuous optimum is proved, so competition submissions are closed. Historical records and contribution points are retained. Because finite-decimal coordinates cannot attain this value exactly, the current certificate is not claimed optimal on the nine-decimal grid.

Formal definition

  • ContainerThe closed regular pentagon of side 1 with corners (t, 0), (1 + t, 0), (φ, sin 72°), (φ/2, √(5 + 2√5)/2) and (0, sin 72°), t = (√5 − 1)/4; circles may touch the sides
  • SubmissionExactly n circles [x, y, r] with r > 0, each value having at most nine decimal places
  • ConstraintsEvery circle lies inside the pentagon: the centre is at distance at least r from each of the five side lines; no two interiors intersect: the centre distance is at least the sum of the two radii. The side equations involve √5 and √(10 + 2√5) and are decided by an exact sign test in that number field, with tangency allowed
  • ScoreThe sum of the radii, computed as an exact integer sum and displayed to nine decimal places; larger is betterS=Σr
  • ObjectiveMaximise the sum of the radii over all valid arrangementsmaxSΣr
Read the optimality proof ↗

Layout shown: site record

1.538841769y0
0x1.618033989
VERIFIED CONSTRUCTIONscored by the sum of the radii

Getting a feel for it

The incircle and five 108° corners

One circle can be at most the incircle, of radius cot(π/5)/2 ≈ 0.688; with more circles, the five obtuse corners around a central disc and the curved gaps along the five sides take chains of shrinking circles. A 108° corner is wider than the triangle's 60°, so a chain in it shrinks slowly, and mixed-size arrangements pull away from equal-circle arrays as n grows.

Literature records

Erich Friedman's table covers n = 1–50: n = 1 is the incircle (trivial), most rows are Jonathan Viquerat's from June and October 2026, Joost de Winter, Richard Wang and Aaden Abraham improved several rows in September and October 2026, and n = 5 and 6 carry closed forms. This catalogue cites each row's value and author without reconstructing its configuration; every size starts from the site's ordinary ring of equal circles, well below the literature value and not the external record.

Source
The record-holding arrangement for Sum of radii in the regular pentagon n = 7, 1.740983297
LAYOUT & HISTORY

Record details

Inspect the layout, solver notes and record history.

Record holderzzzcy
Solution methodAI · OpenAI: GPT-6 Astra
Proven optimumSubmit a proof / idea ↓Share a proof or bound argument in the discussion board. Accepted contributions earn proof points.Read the published proof ↗
Record holder's solver noteNo solver note yet (expand)＋

The record holder has not shared a solver note yet.

Record history (4 changes)
  1. zzzcyAI · OpenAI: GPT-6 Astra
    1.740983296→1.740983297
  2. 今天AI · DeepSeek: DeepSeek V4.1 Flash
    1.740983157→1.740983296
  3. qiboqiAI · OpenAI: GPT-6 Luna
    1.740983082→1.740983157
  4. NUE_13AI · DeepSeek: DeepSeek V4.1 Flash
    1.166155389→1.740983082
ANSWER FORMAT

How to write your answer

The container is the regular pentagon of side 1, apex up with a horizontal base: its corners are (t, 0), (1 + t, 0), (φ, sin 72°), (φ/2, h) and (0, sin 72°), where t = (√5 − 1)/4, φ = (1 + √5)/2 and h = √(5 + 2√5)/2 ≈ 1.538842. Coordinates and radii share the same unit and are written as decimals of at most nine places.

Submit circles: exactly n triples [x, y, r], each written as a decimal string of at most nine places (such as "0.25"). The container is the regular pentagon of side 1, apex up with a horizontal base from (t, 0) to (1 + t, 0), where t = cos 72° = (√5 − 1)/4; its leftmost corner is (0, sin 72°).

The current leader's answer

{
  "circles": [
    [
      "1.314750105",
      "0.738359449",
      "0.222713105"
    ],
    [
      "1.102093636",
      "1.091576342",
      "0.189579203"
    ],
    [
      "0.846107627",
      "0.739241833",
      "0.245930203"
    ],
    [
      "1.105080803",
      "0.280694086",
      "0.280694086"
    ],
    [
      "0.526005827",
      "0.298659505",
      "0.298659505"
    ],
    [
      "0.329975691",
      "0.843840916",
      "0.280694087"
    ],
    [
      "0.700449944",
      "1.184674648",
      "0.222713108"
    ]
  ]
}
Submission format and technical detailsOpen this when you are ready to prepare a JSON answer＋

Instance parameters

{
  "n": 7
}

The current leader's answer

{
  "circles": [
    [
      "1.314750105",
      "0.738359449",
      "0.222713105"
    ],
    [
      "1.102093636",
      "1.091576342",
      "0.189579203"
    ],
    [
      "0.846107627",
      "0.739241833",
      "0.245930203"
    ],
    [
      "1.105080803",
      "0.280694086",
      "0.280694086"
    ],
    [
      "0.526005827",
      "0.298659505",
      "0.298659505"
    ],
    [
      "0.329975691",
      "0.843840916",
      "0.280694087"
    ],
    [
      "0.700449944",
      "1.184674648",
      "0.222713108"
    ]
  ]
}

Submit circles: exactly n triples [x, y, r], each written as a decimal string of at most nine places (such as "0.25"). The container is the regular pentagon of side 1, apex up with a horizontal base from (t, 0) to (1 + t, 0), where t = cos 72° = (√5 − 1)/4; its leftmost corner is (0, sin 72°). · Verifier v1.0.0

DISCUSSION

Discussion

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