The most erasure-robust measurement directions · d = 3, n = 6
Also known asfull spark frameserasure-robust framesmaximally robust to erasuresnumerically erasure-robust frames
Choose n nonzero vectors in Rᵈ. For every subset of size d, take the squared determinant of the matrix with those vectors as columns, divided by the product of their squared norms; maximize the minimum of this normalized volume over all subsets. Zero means some d surviving measurements cannot recover the space at all.
Record comparison
the worst subset's normalized volume · Higher is better| Record | Value / interval | Author / holder | Source |
|---|---|---|---|
| Proven optimum | (2/5)(1 − 1/√5) | zzzcy #308 | MinMax Arena ↗ |
| Site record | 0.2211145618 | zzzcy | Record details ↓ |
The continuous optimum is proved, so competition submissions are closed. Historical records and contribution points are retained. Because finite-decimal coordinates cannot attain this value exactly, the current certificate is not claimed optimal on the nine-decimal grid.
Formal definition
- ContainerReal d-space Rᵈ; an answer is n measurement directions
- SubmissionExactly n nonzero vectors with d coordinates each
- ScoreS ranges over all C(n,d) subsets of size d, and Vₛ is the d×d matrix whose columns are those vectors. V(P) is the worst subset's squared normalized determinant, compared directly in exact rational arithmetic by cross-multiplication
- WordingThis problem measures erasure robustness by the minimum squared normalized volume over all d-element subsets, capturing how far the worst surviving basis stays from degeneracy
- ScoringThe record is stored as floor(min normalized volume · 10¹⁸); the page displays that value, rounded down at the twelfth decimal
- ObjectiveMake V(P) as large as possible over all legal families of measurement directions P