P12 · 装箱与覆盖 · 经典问题 · 难

2:1 长方形内的等圆装箱 · n = 98

文献中也称circles in a rectanglepacking equal circles in a 2:1 rectangle

在 2 × 1 的长方形内放置 n 个互不重叠的等圆,使它们的共同半径尽可能大。

子题n = 98
目标最大化 共同半径

纪录对比

共同半径 · 越大越好
纪录数值 / 区间作者 / 持有人来源
外部已知最好[0.072953911558221449942068202613, 0.072953911558221449942068202615]Eckard Specht2010-08-10Packomania ↗
本站纪录0.072956792condor纪录详情 ↓

已超越外部纪录 · 审核通过。 审核依据 ↗

严格定义

  • 容器宽 2、高 1 的长方形 [0, 2] × [0, 1],左下角为原点 (0, 0),右上角为 (2, 1)
  • 提交恰好 n 个圆:一个共同半径 radius 与 n 个圆心坐标 centers
  • 约束每个圆完全位于长方形内;任意两圆内部不重叠,允许相切
  • 目标最大化共同半径 radius
挑战这个纪录 ↗

当前展示:本站纪录

1y0
0x2
已验证构造r = 0.072956792

帮助理解

交错之字层与行转换

在长宽比为 2 : 1 的狭长容器内,小规模时各圆通常交替贴靠上下长边排成之字形链;随着 n 增大,排布会在双层交错、三层蜂窝与局部斜排之间切换。除了完美契合 2 : 1 比例的偶数网格(如 2 × 1 或 4 × 2)外,整齐的轴对齐网格通常会浪费横向或纵向空间。

已知证明与开放前沿

n = 3..6 的最优半径可通过之字形链的初等几何下界严格证明(详见各子题的已知最优说明);更大的 n 引用 Packomania 的 1 × 0.5 长方形表(本题是它放大两倍,半径也乘 2),表中只列出最优已知值,没有一项标为已证明最优。

2:1 长方形内的等圆装箱 n = 98 的当前纪录构型,0.072956792
构型与历史

纪录详情

查看构型、求解笔记与纪录历史。

纪录保持者condor
解题方式AI · OpenAI: GPT-6.1 Sol
挑战这个纪录 ↗提交证明 / 思路 ↓在讨论区分享最优性证明或关键界限思路,经审核采纳后可获证明分。
纪录保持者的求解笔记暂无求解笔记(点击展开)+

纪录保持者暂未分享求解过程。

历史纪录(5 次易主)
  1. condorAI · OpenAI: GPT-6.1 Sol
    0.072956176→0.072956792
  2. Joost de WinterAI · OpenAI: GPT-6.1 Sol
    0.072953913→0.072956176
  3. condorAI · OpenAI: GPT-6 Astra
    0.072953911→0.072953913
  4. NUE_13AI · DeepSeek: DeepSeek V4.1 Flash
    0.071428571→0.072953911
  5. NUE_13人工
    0.057142856→0.071428571
ANSWER FORMAT

答案怎么写

容器是宽 2、高 1 的长方形,左下角是原点 (0, 0),右上角是 (2, 1)。坐标和长度用同一个单位,直接写成小数,例如 "0.25",最多九位小数。

提交共同半径 radius 与各圆圆心坐标 centers,所有数值均以十进制字符串表示(如 "0.25")。

当前第一名的答案

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}
提交格式与技术细节需要编写程序或准备 JSON 答案时再查看+

子题参数

{
  "n": 98
}

当前第一名的答案

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}

提交共同半径 radius 与各圆圆心坐标 centers,所有数值均以十进制字符串表示(如 "0.25")。 · 验证器 v1.0.0

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