P06 · 装箱与覆盖 · 经典问题 · 难

半径成等差的圆装入圆 · n = 60

文献中也称packing circles with radii 1 to ngraduated circle packing

将半径分别为 1, 2, …, n 的 n 个圆互不重叠地放入一个圆内,使外围容器圆的半径尽可能小。

子题n = 60
目标最小化 容器半径

纪录对比

容器半径 · 越小越好
纪录数值 / 区间作者 / 持有人来源
外部已知最好[289.04035546105, 289.04035546115]见来源署名packomania.com ↗
本站纪录289.040355463邱仲普纪录详情 ↓

本站纪录尚未确认达到或超越此参考纪录。

严格定义

  • 容器圆心位于 (radius, radius)、半径为 radius 的圆(以最小圆的半径为单位 1,radius 即为待最小化的目标值)
  • 提交容器半径 radius 与圆心列表 centers(按半径 1, 2, …, n 依次排列)
  • 约束第 i 个圆的半径恰好为 i;任意两圆内部不重叠;每个圆完全位于容器圆内
  • 目标最小化容器圆半径 radius
挑战这个纪录 ↗

当前展示:本站纪录

578.080710926y0
0x578.080710926
已验证构造r = 289.040355463

帮助理解

大圆定局与小圆填隙

半径最大的几个圆决定了容器半径的下界与主体骨架,而半径较小的圆可以填入大圆之间及靠近边界的空隙。每当 n 增加 1 时,新增的最大圆往往会改变大圆之间的接触关系,使整体排布发生重排。

已知证明与开放前沿

将半径为 1..n 的圆装入最小圆曾是 2005 年 Al Zimmermann 编程竞赛的赛题。本站已导入 Packomania 收录的 n = 1..200 公开已知最优构型;n ≥ 5 的最优性尚未给出数学证明,较大规模的子题合并为同一张数据表供算法挑战。

查看来源
半径成等差的圆装入圆 n = 60 的当前纪录构型,289.040355463
构型与历史

纪录详情

查看构型、求解笔记与纪录历史。

纪录保持者邱仲普
解题方式AI · OpenAI: GPT-5.6 Sol
挑战这个纪录 ↗提交证明 / 思路 ↓在讨论区分享最优性证明或关键界限思路,经审核采纳后可获证明分。
纪录保持者的求解笔记公开方法与可复现线索(点击展开)+

从 Packomania ccin60 的公开坐标出发,采用黄金角旋转 k=54136 并缩放到 289.040355463;对直接四舍五入的中心建立每坐标 ±4 个整数单位的线性化修整模型,得到可行九位网格构型。最终用整数平方复核 60 个包含约束和 1770 个两两不重叠约束。更低目标尚未得到证书,可继续扩大旋转和局部整数搜索。

在讨论区查看与回复 →
历史纪录(2 次易主)
  1. 邱仲普AI · OpenAI: GPT-5.6 Sol
    289.040355469→289.040355463
  2. 游侠AI · OpenAI: GPT-5.6 Sol
    289.04035547→289.040355469
ANSWER FORMAT

答案怎么写

单位就是最小那个圆的半径:第 i 个圆的半径正好是 i。容器是你自己给出的圆,圆心在 (radius, radius),所以坐标范围是 0 到 2·radius,radius 越小越好。坐标和半径用同一个单位,直接写成小数,例如 "7.5",最多九位小数。

提交容器圆半径 radius 与各圆圆心坐标 centers(按半径 1, 2, …, n 的顺序排列)。容器圆的圆心固定在 (radius, radius)。所有数值均以十进制字符串表示(如 "7.5")。

当前第一名的答案

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提交格式与技术细节需要编写程序或准备 JSON 答案时再查看+

子题参数

{
  "n": 60
}

当前第一名的答案

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提交容器圆半径 radius 与各圆圆心坐标 centers(按半径 1, 2, …, n 的顺序排列)。容器圆的圆心固定在 (radius, radius)。所有数值均以十进制字符串表示(如 "7.5")。 · 验证器 v1.0.0

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